X^2+1.5x-0.1=0

Solution for X^2+1.5x-0.1=0 equation:

X^2+1.5X-0.1=0

a = 1; b = 1.5; c = -0.1;
Δ = b2-4ac
Δ = 1.52-4·1·(-0.1)
Δ = 2.65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{2.65}}{2*1}=\frac{-1.5-\sqrt{2.65}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{2.65}}{2*1}=\frac{-1.5+\sqrt{2.65}}{2}
$